Center of MassHard
Question
The fig. shows a string of equally spaced beads of mass m, separated by distance d. The beads are free to slide without friction on a thin wire. A constant force F acts on the first bead initially at rest till it makes collision with the second bead. The second bead then collides with the third and so on. Suppose all collisions are elastic, then :
Options
A.speed of the first bead immediately before and immediately after its collision with the second bead is 
and zero respectively.
and zero respectively.B.speed of the first bead immediately before and immediately after its collision with the second bead is and 
respectively.
and respectively.C.speed of the second bead immediately after its collision with third bead is zero.
D.the average speed of the first bead is .
.Solution
a = 
for elastic collission e = 1
v12 = 0 + 2ad
vb12 =
. d vb1 =
after collision vb2 = 0.
for elastic collission e = 1v12 = 0 + 2ad
vb12 =
. d vb1 =after collision vb2 = 0.
Create a free account to view solution
View Solution FreeMore Center of Mass Questions
A sphere of mass m1 = 2kg collides with a sphere of mass m2 = 3kg which is at rest. Mass m1 will move at right angle to ...Two particles of equal mass m are projected form the ground with speed v1 and v2 at angle θ1 and θ2 as shown i...The centre of mass of two masses m & m′ moves by a distance when mass m is moved by distance x and m′ is kep...A particle of mass ′m′ and velocity ′′ collides oblique elastically with a stationary particle o...A massive ball moving with speed v collides head-on with a tiny ball at rest having a mass very less than the mass of th...