Center of MassMedium
Question
The fig. shows a string of equally spaced beads of mass m, separated by distance d. The beads are free to slide without friction on a thin wire. A constant force F acts on the first bead initially at rest till it makes collision with the second bead. The second bead then collides with the third and so on. Suppose all collisions are elastic, then :
Options
A.speed of the first bead immediately before and immediately after its collision with the second bead is 
and zero respectively.
and zero respectively.B.speed of the first bead immediately before and immediately after its collision with the second bead is and 
respectively.
and respectively.C.speed of the second bead immediately after its collision with third bead is zero.
D.the average speed of the first bead is .
.Solution
a = 
for elastic collission e = 1
v12 = 0 + 2ad
vb12 =
. d vb1 =
after collision vb2 = 0.
for elastic collission e = 1v12 = 0 + 2ad
vb12 =
. d vb1 =after collision vb2 = 0.
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