Center of MassHard
Question
The fig. shows a string of equally spaced beads of mass m, separated by distance d. The beads are free to slide without friction on a thin wire. A constant force F acts on the first bead initially at rest till it makes collision with the second bead. The second bead then collides with the third and so on. Suppose all collisions are elastic, then :
Options
A.speed of the first bead immediately before and immediately after its collision with the second bead is 
and zero respectively.
and zero respectively.B.speed of the first bead immediately before and immediately after its collision with the second bead is and 
respectively.
and respectively.C.speed of the second bead immediately after its collision with third bead is zero.
D.the average speed of the first bead is .
.Solution
a = 
for elastic collission e = 1
v12 = 0 + 2ad
vb12 =
. d vb1 =
after collision vb2 = 0.
for elastic collission e = 1v12 = 0 + 2ad
vb12 =
. d vb1 =after collision vb2 = 0.
Create a free account to view solution
View Solution FreeMore Center of Mass Questions
Two particles A and B each of mass m are attached by a light inextensible string of length 2l. The whole system lies on ...Two identical photo cathodes receive light of frequencies f1 and f2. if the velocities of the photoelectrons (of mass m)...A uniform rod of mass m and length 2l lies on smooth horizontal surface. A particle of same mass m is connected to strin...A body of mass 1 kg moving in the x-direction, suddenly explodes into two fragments of mass 1/8 kg and 7/8 kg. An instan...A disc of radius a/4 is removed from a square plate of side a as shown in figure then what will be distance of centre of...