Center of MassHard
Question
A particle strikes a horizontal smooth floor with a velocity u making an angle θ with the floor and rebounds with velocity v making an angle φ with the floor. If the coefficient of restitution between the particle and the floor is e, then :
Options
A.the impulse delivered by the floor to the body is mu(1 + e) sin θ.
B.tan φ = e tan θ.
C.v = u
D.the ratio of the final kinetic energy to the initial kinetic energy is (cos2 θ + e2 sin2 θ)
Solution
vcosφ = ucosθ
vsinφ = eusinθ
v2 =
v =
∴ v = u
tanφ = etanθ.
I = m (vLOI − uLOI)
= m (eusinθ − usinθ)
= mu (1 + e) sinθ.
ki =
mu2 kf = mv2
= 
= cos2θ + e2 sin2θ.Create a free account to view solution
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