Center of MassHard
Question
A particle of mass m strikes elastically with a disc of radius R, with a velocity 
as shown in the figure. If the mass of the disc is equal to that of the particle and the surface of the contact is smooth, then the velocity of the disc just after the collision is :
as shown in the figure. If the mass of the disc is equal to that of the particle and the surface of the contact is smooth, then the velocity of the disc just after the collision is :Options
A.2v/3
B.v/2
C.√3v/2
D.v
Solution
sin θ = 
; θ = 30o
Both have equal mass it means along LOI particle transfer it velocity to disc which is vcos θ.
so VD = Vcos θ = Vcos 30º =
; θ = 30oBoth have equal mass it means along LOI particle transfer it velocity to disc which is vcos θ.
so VD = Vcos θ = Vcos 30º =
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