Center of MassHard
Question
A stationary body explodes into four identical fragments such that three of them fly off mutually perpendicular to each other, each with same K.E., E0 . The minimum energy of explosion will be:
Options
A.6E0
B.4E0/3
C.4E0
D.4E0
Solution
Using momentum conservation
K. E1 =
= E0 + E0 + E0
Total energy = 3E0 + E0 + E0 + E0 = 6E0
K. E1 =
= E0 + E0 + E0Total energy = 3E0 + E0 + E0 + E0 = 6E0
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