Momentum and CollisionMedium
Question
A stationary body explodes into four identical fragments such that three of them fly off mutually perpendicular to each other, each with same K.E., E0 . The minimum energy of explosion will be:
Options
A.6E0
B.4E0/3
C.4E0
D.4E0
Solution
Using momentum conservation
K. E1 =
= E0 + E0 + E0
Total energy = 3E0 + E0 + E0 + E0 = 6E0
K. E1 =
= E0 + E0 + E0Total energy = 3E0 + E0 + E0 + E0 = 6E0
Create a free account to view solution
View Solution FreeMore Momentum and Collision Questions
A steel rod of cross-sectional area 16 cm2 and two brass rods of cross section area 10 cm2 together support a load of 50...A square box of water has a small hole located in one of the bottom corner. When the box is full and sitting on a level ...A small ball is left in a viscous liquid form very much height. Correct graph of its velocity with time is : -...A light body A and a heavy body B have equal linear momentum. Then the K.E. of the body A:-...The diagram (figure) shows a venturesome, through which water is flowing. The speed of water at X is 2 cm/s. The speed o...