Center of MassHard
Question
A train of mass M is moving on a circular track of radius ′R′ with constant speed V. The length of the train is half of the perimeter of the track. The linear momentum of the train will be
Options
A.0
B.
C.MVR
D.MV
Solution
(B) If we treat the train as a ring of mass ′M′ then its COM will be at a distance from the centre of the circle. Velocity of centre of mass is :
VCM = RCM .ω
=
.ω = 
(∵ ω = 
)
⇒ VCM =
⇒ MVCM = 
As the linear momentum of any system = MVCM
∴ The linear momentum of the train =
VCM = RCM .ω
=
.ω = (∵ ω = )⇒ VCM =
⇒ MVCM = As the linear momentum of any system = MVCM
∴ The linear momentum of the train =
Create a free account to view solution
View Solution FreeMore Center of Mass Questions
A balloon having mass ′m′ is filled with gas and is held in hands of a boy. Then suddenly it get released an...Two men ′A′ and ′B′ are standing on a plank. ′B′ is at the middle of the plank and &...The centre of mass of a body :...A stationary body explodes into two fragments of masses m1 and m2. If momentum of one fragment is p, the minimum energy ...A ball moving with a velocity v hits a massive wall moving towards the ball with a velocity u. An elastic impact lasts f...