Center of MassHard
Question
A skater of mass m standing on ice throws a stone of mass M with a velocity of v in a horizontal direction. The distance over which the skater will move back (the coefficient of friction between the skater and the ice is μ) :
Options
A.
B.
C.
D.
Solution
Pi = 0 ...(i)
Pf = MV − mV1 ....(ii)
MV − mV1 = 0 ⇒ u =
V.using V12 = u2 + 2ax.
a = mg.
= 0 + 2μg x.∴ x =
Create a free account to view solution
View Solution FreeMore Center of Mass Questions
A tube of length L is filled completely with an imcompressible liquid of mass M closed at both the ends. The tube is the...A semicircular portion of radius ′r′ is cut from a uniform rectangular plate as shown in figure. The distanc...Two bodies of same mass collide head on elastically then...Two identical charged spheres suspended from a common point by two massless strings of lengths ð‘™, areinitially at a d...A ball of mass m strikes the fixed inclined plane after falling through a height h. If it rebounds elastically, the impu...