Momentum and CollisionMedium
Question
A skater of mass m standing on ice throws a stone of mass M with a velocity of v in a horizontal direction. The distance over which the skater will move back (the coefficient of friction between the skater and the ice is μ) :
Options
A.
B.
C.
D.
Solution
Pi = 0 ...(i)
Pf = MV − mV1 ....(ii)
MV − mV1 = 0 ⇒ u =
V.using V12 = u2 + 2ax.
a = mg.
= 0 + 2μg x.∴ x =
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