Indefinite IntegrationHard

Question

The value of dx is equal to:

Options

A.x ln (1 + sinx) + C
B.ln (1 + sin x) + C
C.- x ln (1 + sin x) + C
D.ln (1 - sin x) + C

Solution

dx
= ∫ ln (1 + sin x) dx + ∫x tan dx
=  x.ln (1+ sin x) - cos x . x dx + ∫x tan dx
= x.ln (1 + sin x) - . x dx + ∫x tandx
= x ln (1 + sinx) + C

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