Indefinite IntegrationHard
Question
The value of ∫ 4 sin x cos
cos
dx is equal to
Options
A.cos x -
cos 2x +
cos 3x + C
B.cos x -
cos 2x -
cos 3x + C
C.cos x +
cos 2x +
cos 3x + C
D.cos x +
cos 2x -
cos 3x + C
Solution
∫4sin x cos
cos
dx
= ∫2 sin x(cos 2x + cos x) dx
= ∫2sin x cos 2x dx + ∫sin 2x dx
= ∫(sin 3x - sinx + sin2x) dx
= cos x -
cos 2x -
cos 3x + C
= ∫2 sin x(cos 2x + cos x) dx
= ∫2sin x cos 2x dx + ∫sin 2x dx
= ∫(sin 3x - sinx + sin2x) dx
= cos x -
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