Indefinite IntegrationHard
Question
If 
dx = A cos 4x + B; where A & B are constants, then
dx = A cos 4x + B; where A & B are constants, then Options
A.A = - 1/4 & B may have any value
B.A = - 1/8 & B may have any value
C.A = - 1/2 & B = - 1/4
D.A = - 1/2 & B = - 1/4
Solution
dx = A cos 4x + BL.H.S.
= ∫2 cos 2xsin x cos xdx = 
∫sin 4x dx=
+ B = - 
cos4 x - BCreate a free account to view solution
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