Center of MassHard
Question
In the arrangement shown, the pendulum on the left is pulled aside. It is then released and allowed to collide with other pendulum which is at rest. A perfectly inelastic collision occurs and the system rises to a height h/4 . The ratio of the masses (m1 / m2) of the pendulum is :
Options
A.1
B.2
C.3
D.4
Solution
m1
+ 0 = (m1 + m2)vv =
∴ v2 − u2 + 2g ×
= 6 + 2g × 
= 
∴ v =
Also,
= 
⇒ 2m1 + m1 + m2∴
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