Center of MassHard
Question
A thin uniform wire is bent to form the two equal sides AB and AC of triangle ABC, where
AB = AC = 5 cm. The third side BC, of length 6cm, is made from uniform wire of twice the density of the first. The distance of centre of mass from A is :
AB = AC = 5 cm. The third side BC, of length 6cm, is made from uniform wire of twice the density of the first. The distance of centre of mass from A is :
Options
A.
cm
cmB.
cm
cmC.
cm
cmD.
cm
cm
= 
= 
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