Indefinite IntegrationHard

Question

The value of ∫tan3 2 x sec 2 x dx is equal to :

Options

A.1/3 sec3 2 x - 1/2 sec 2 x + C
B.- 1/6 sec3 2 x - 1/2 sec 2 x + C
C.1/6 sec3 2 x - 1/2 sec 2 x + C
D.1/3 sec3 2x + 1/2 sec 2x + C

Solution

∫tan3 2x. sec 2x dx
I = ∫(sec2 2x - 1)sec 2x.tan 2x dx  Put sec 2x = t   ⇒  2 sec 2x tan 2x dx = dt
⇒ I = ∫(t2 - 1) dt
= sec3 2x - sec 2x + C

Create a free account to view solution

View Solution Free
Topic: Indefinite Integration·Practice all Indefinite Integration questions

More Indefinite Integration Questions

equals-...dx is equal to-...If g(x) dx = g(x), theng(x) {f(x) + f′ (x)} is equal to-...sin x sec3 x dx equals-...dx equals-...