Indefinite IntegrationHard
Question
If y = 
and y = 0 when x = 0, then value of y when x = 1, is:
and y = 0 when x = 0, then value of y when x = 1, is:Options
A.
B.√2
C.3√2
D.
Solution
y = 
put 1 + 
= t2 ⇒ - 
dx = 2t dt
⇒ y =
∵ y (0) = 0 ⇒ C = 0
∴ y(1) =
put 1 + = t2 ⇒ - dx = 2t dt⇒ y =
∵ y (0) = 0 ⇒ C = 0
∴ y(1) =
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