FunctionHard

Question

Let {θ : sin θ - cosθ = √2 cos θ} and Q = {θ : sin θ + cosθ = √2 sinθ} be two sets. Then

Options

A.
B.
C.
D.P = Q

Solution

In set P, sinθ = (√2 + 1) cos θ ⇒ tan θ = √2 + 1
In set Q, (√2 - 1) sin θ = cos θ ⇒ tan θ = √2 + 1 ⇒ P = Q

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