FunctionHard
Question
Let f(x) = 
, 0 ≤ x ≤1 and g(x) = 4x (1 - x), 0 ≤ x ≤ 1, then
, 0 ≤ x ≤1 and g(x) = 4x (1 - x), 0 ≤ x ≤ 1, then Options
A.fog = 
, 0 ≤ x ≤ 1
, 0 ≤ x ≤ 1B.fog = 
≤ x ≤ 1
≤ x ≤ 1C.gof = 
≤ x ≤ 1
≤ x ≤ 1D.gof = 
≤ x ≤ 1
≤ x ≤ 1Solution
f(x) = 
, 0 ≤ x ≤ 1
g(x) = 4x (1 - x),0 ≤ x ≤ 1
fog(x) =
gof(x) = 4f(x) . (1 - f(x))
= 4
=
, 0 ≤ x ≤ 1 g(x) = 4x (1 - x),0 ≤ x ≤ 1
fog(x) =
gof(x) = 4f(x) . (1 - f(x))
= 4
=
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