FunctionHard
Question
Let f(x) = 
, 0 ≤ x ≤1 and g(x) = 4x (1 - x), 0 ≤ x ≤ 1, then
, 0 ≤ x ≤1 and g(x) = 4x (1 - x), 0 ≤ x ≤ 1, then Options
A.fog = 
, 0 ≤ x ≤ 1
, 0 ≤ x ≤ 1B.fog = 
≤ x ≤ 1
≤ x ≤ 1C.gof = 
≤ x ≤ 1
≤ x ≤ 1D.gof = 
≤ x ≤ 1
≤ x ≤ 1Solution
f(x) = 
, 0 ≤ x ≤ 1
g(x) = 4x (1 - x),0 ≤ x ≤ 1
fog(x) =
gof(x) = 4f(x) . (1 - f(x))
= 4
=
, 0 ≤ x ≤ 1 g(x) = 4x (1 - x),0 ≤ x ≤ 1
fog(x) =
gof(x) = 4f(x) . (1 - f(x))
= 4
=
Create a free account to view solution
View Solution FreeMore Function Questions
If the domain of function f(x) = x2 − 6x + 7 is (−∞, ∞), then the range of function is -...f(x) = |x - 1|, f: R+ → R, g(x) = ex, g : [- 1, ∞) → R. If the function fog (x) is defined, then its d...If f (x + ay, x - ay ) = axy then f (x, y) is equal to-...Solution of ≥ 3 is-...Which of the following function is onto ?...