CapacitanceHard
Question
A parallel plate condenser of capacity C is connected to a battery and is charged to potential V. Another condenser of capacity 2C is connected to another battery and is charged to potential 2V. The charging batteries are removed and now the condensers are connected in such a way that the positive plate of one is connected to negative plate of another. The final energy of this system is -
Options
A.zero
B.
C.
D.
Solution
Total charge = 4 CV − CV = 3 CV
Now, let it is distributed as shown, potential across the capacitors is same
So,
⇒ q = 2 CV
Total potential energy =
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