CapacitanceHard
Question
The plate separation in a parallel plate condenser is d and plate area is A. If it is charged to V volt & battery is disconnected then the work done in increasing the plate separation to 2d will be-
Options
A.
B.
C.
D.
Solution
As battery is disconnected, charge remains constant in the work process.
Work done = final potential energy - initial potential energy
=
=
Where , Q = CV =
, C = 
, C′ = 
Now, work done =
Ans. is (D)
Work done = final potential energy - initial potential energy
=
=
Where , Q = CV =
, C = , C′ = Now, work done =
Ans. is (D) Create a free account to view solution
View Solution FreeMore Capacitance Questions
A parallel plate condenser with plate separation d is charged with the help of a battery so that U0 energy is stored in ...A lamp of 100 W and a heater of 1 kW are in simultaneous use for 10 hours. The units of electricity consumed according t...A capacitor of 0.2 μF capacitance is charged to 600 V. On removing the battery, it is connected with a 1.0 μF ...Choose the incorrect statement from the following When two identical capacitors are charged individually to different po...The resistance of an electric bulb marked 220 V, 100 W is :-...