CapacitanceHard
Question
The work done against electric forces in increasing the potential difference of a condenser from 20V to 40V is W. The work done in increasing its potential difference from 40V to 50V will be (consider capacitance of capacitor remain constant)
Options
A.4W
B.3W/4
C.2W
D.W/2
Solution
W = Uf − Ui = 
CVf2 − 
CVi2 = C (402 − 202) W = 600 C
W1 = C (502 − 402) = 
C W1 = 
W
CVf2 − CVi2 = C (402 − 202) W = 600 CW1 =
C (502 − 402) = C W1 = WCreate a free account to view solution
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