Permutation and CombinationHard
Question
Assuming the balls to be identical except for difference in colours, the number of ways in which one or more balls can be selected from10 white, 9 green and 7 black balls is :-
Options
A.879
B.880
C.629
D.630
Solution
W10, G9, B7
selection of one or more balls
= (10 + 1) (9 + 1) (7 + 1) - 1
= 11 × 10 × 8 - 1
= 879
selection of one or more balls
= (10 + 1) (9 + 1) (7 + 1) - 1
= 11 × 10 × 8 - 1
= 879
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