Differential EquationHard
Question
The solution of the differential equation 
- ky = 0,y(0) = 1, approaches zero when x → ∞, if
- ky = 0,y(0) = 1, approaches zero when x → ∞, if Options
A.k = 0
B.k > 0
C.k < 0
D.none of these
Solution
- ky = 0, 
= kdxlny = kx + c
at x = 0, y = 1 ∴ c = 0
Now lny = kx
y = ekx
y = 
ekx = 0∴ k < 0
Create a free account to view solution
View Solution FreeMore Differential Equation Questions
If y = e(k + 1)x is a solution of differential equation + 4y= 0, then k =...The solution of the differential equation x = y (log y − log x + 1) is-...The solution of (x)dx + (y)dy = 0 is -...The solution of the differential equation ydx + (x + x2 y) dy = 0 is -...The function y = f(x) is the solution of the differential equation in (- 1, 1) satisfying f(0) = 0. Then f(x) dx is...