Differential EquationHard
Question
The solution of the differential equation 
- ky = 0,y(0) = 1, approaches zero when x → ∞, if
- ky = 0,y(0) = 1, approaches zero when x → ∞, if Options
A.k = 0
B.k > 0
C.k < 0
D.none of these
Solution
- ky = 0, 
= kdxlny = kx + c
at x = 0, y = 1 ∴ c = 0
Now lny = kx
y = ekx
y = 
ekx = 0∴ k < 0
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