Differential EquationHard

Question

The solution of x2 y12 + xy y1 - 6y2 = 0 are

Options

A.y = Cx2
B.x2 y = C
C.ln y = C + log x
D.x3 y = C

Solution

x2 y12 + xy y1 - 6y2 = 0
It is quadratic equation in y1
y1 = b
y1 = -   |    y1 =
   |   
   |  
- ln y = 3 lnx + lnc     |    lny = 2 lnx + lnc
x3y = C                             y = cx2
Option  (C)
log y = c + logx
log y = ln c1 + logx2
y = C1x2

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