Differential EquationHard
Question
The solution of x2 y12 + xy y1 - 6y2 = 0 are
Options
A.y = Cx2
B.x2 y = C
C.
ln y = C + log x
ln y = C + log xD.x3 y = C
Solution
x2 y12 + xy y1 - 6y2 = 0
It is quadratic equation in y1
y1 =
b
y1 = -
| y1 = 
| 
| 
- ln y = 3 lnx + lnc | lny = 2 lnx + lnc
x3y = C y = cx2
Option (C)
log y = c + logx
log y = ln c1 + logx2
y = C1x2
It is quadratic equation in y1
y1 =
by1 = -
| y1 = | | - ln y = 3 lnx + lnc | lny = 2 lnx + lnc
x3y = C y = cx2
Option (C)
log y = c + logxlog y = ln c1 + logx2
y = C1x2
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