Alternating CurrentHard
Question
A circuit is set up by connecting L = 100 mH, C = 5 πF and R =100 Ω in series. An alternating emf of (150√2) volt, 500/π Hz is applied across this series combination. Which of the following is correct
Options
A.the impedance of the circuit is 141.4 Ω
B.the average power dissipated across resistance 225 W
C.the average power dissipated across resistance 225 W
D.the average power dissipated across capacitor is zero.
Solution
Z = 
= 100√2
Irms =
PR = Irms2 R
PL = 0
PC = 0
= 100√2Irms =
PR = Irms2 R
PL = 0
PC = 0
Create a free account to view solution
View Solution FreeMore Alternating Current Questions
A generator produces a voltage V = 240 sin 120t volt where V is in volts and t in second. The frequency and r.m.s. volta...A choke coil sould have :...A 50 Hz a.c source of 20 volt is connected across Rand C as show in figure. The voltage across R is 12 volt. The voltage...A pure inductance of 1 henry is connected across a 110 V, 70Hz source. Then correct option are(Use π = 22/7):...Flash light equipped with a new set of batteries, produces bright light. As the batteries wear out:...