Alternating CurrentHard
Question
A circuit is set up by connecting L = 100 mH, C = 5 πF and R =100 Ω in series. An alternating emf of (150√2) volt, 500/π Hz is applied across this series combination. Which of the following is correct
Options
A.the impedance of the circuit is 141.4 Ω
B.the average power dissipated across resistance 225 W
C.the average power dissipated across resistance 225 W
D.the average power dissipated across capacitor is zero.
Solution
Z =
= 100√2
Irms =
PR = Irms2 R
PL = 0
PC = 0
Irms =
PR = Irms2 R
PL = 0
PC = 0
Create a free account to view solution
View Solution FreeMore Alternating Current Questions
An inductance of 0.4 Henry and a resistance of 100 ohm are connected to a A.C. voltage source of 220 V and 50 Hz. Then f...If the current through an inductor of inductance L is given by I = I0 sinωt, then the voltage across inductor will ...The diagram shows a capacitor C and a resistor R connected in series to an AC source, V1 and V2 are voltmeters and A is ...An inductor coil of inductance L is into two equal parts and both the parts are connected in parallel. The net inductanc...If frequency of alternating source is made zero then which of the following statement is true :-...