Alternating CurrentHard

Question

A series LCR circuit containing a resistance of 120 ohm has angular resonance frequency 4 × 103 rad s-1. At resonance, the voltage across resistance and inductance are 60V and 40 V respectively. The values of L and C are respectively :

Options

A.20 mH, 25/8 μF
B.2 mH, 1/35 μF
C.20 mH, 1/40 μF
D.2 mH, 25/8 μF

Solution

Irms = = Amp.
VL = Irms × (ωL)
40 = × (40 × 103) × L
L = 20 mH
At resonance          VC = Irms = VL
C =
C = mF.

Create a free account to view solution

View Solution Free
Topic: Alternating Current·Practice all Alternating Current questions

More Alternating Current Questions