Alternating CurrentHard
Question
In an L-R series circuit (L = 
μH and R = 12Ω), a variable emf source (V = V0 sin ωt) of Vrms = 130 √2 V and frequency 50 Hz is applied. The current amplitude in the circuit and phase of current with respect to voltage are respectively(Use π = 22/7)
μH and R = 12Ω), a variable emf source (V = V0 sin ωt) of Vrms = 130 √2 V and frequency 50 Hz is applied. The current amplitude in the circuit and phase of current with respect to voltage are respectively(Use π = 22/7)Options
A.14.14A, 30o
B.10 √2 A, tan-1 
C.10 A, tan-1
D.20 A, tan-1
Solution
I0 = √2 Irms = 
I0 =
tan φ =
φ = tan-1
.
I0 =
tan φ =
φ = tan-1
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