Alternating CurrentMedium
Question
A pure resistive circuit element X when connected to an AC supply of peak voltage 200 V gives a peak current of 5 A which is in phase with the voltage. A second circuit element Y, when connected to the same AC supply also gives the same value of peak current but the current lags behind by 90o. If the series combination of X and Y is connected to the same supply, what will be the rms value of current ?
Options
A.
amp
ampB.
amp
ampC.
amp
ampD.5 amp
Solution
R = 
= 40 Ω (For circuit x)
XL =
= 40 Ω (For circuit x)
If x & y are in series
I =
Amp. ⇒ Irms = 
amp.
= 40 Ω (For circuit x)XL =
= 40 Ω (For circuit x)If x & y are in series
I =
Amp. ⇒ Irms = amp.Create a free account to view solution
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