Alternating CurrentHard
Question
A pure resistive circuit element X when connected to an AC supply of peak voltage 200 V gives a peak current of 5 A which is in phase with the voltage. A second circuit element Y, when connected to the same AC supply also gives the same value of peak current but the current lags behind by 90o. If the series combination of X and Y is connected to the same supply, what will be the rms value of current ?
Options
A.
amp
ampB.
amp
ampC.
amp
ampD.5 amp
Solution
R = 
= 40 Ω (For circuit x)
XL =
= 40 Ω (For circuit x)
If x & y are in series
I =
Amp. ⇒ Irms = 
amp.
= 40 Ω (For circuit x)XL =
= 40 Ω (For circuit x)If x & y are in series
I =
Amp. ⇒ Irms = amp.Create a free account to view solution
View Solution FreeMore Alternating Current Questions
An inductor coil of inductance L is into two equal parts and both the parts are connected in parallel. The net inductanc...A shorticircuited coil is placed in a time verying magnetic field. Electric power is disspated due to the current induce...An inductance has a high resistance to a.c. and low to D.C., when a dc voltage source having some ac component superimpo...A generator produces a voltage V = 240 sin 120t volt where V is in volts and t in second. The frequency and r.m.s. volta...Average power consumed in an A.C. series circuit is given by (symbols have their usual meaning) :...