Definite IntegrationHard
Question
The area inside the parabola 5x2 - y = 0 but outside the parabola 2x2 - y + 9 = 0 is
Options
A.12√3
B.6√3
C.8√3
D.4√3
Solution
y1 = 5x2
y2 = 2x2 + 9
A(- √3, 15)
B(√3, 15)
Area = 2
dx = 2 
= 2(9√3 - 3√3) = 12√3
y2 = 2x2 + 9
A(- √3, 15)
B(√3, 15)
Area = 2
dx = 2 = 2(9√3 - 3√3) = 12√3
Create a free account to view solution
View Solution FreeMore Definite Integration Questions
is equal to-...The area bounded by the curve y = 2x4 - x2, x-axis and the two ordinates corresponding to the minima of the function is...If f(x) = dt, then f (x + π) is equal to :...Let f(x) = minimum (|x|, 1 - |x|, 1/4) , ∀ x ∈ R, then the value ofdx is equal to...The value of (x2 + ex ) dx is-...