Definite IntegrationHard
Question
Let In = 
tan n x dx, then 
, .... are in :
tan n x dx, then , .... are in :Options
A.A.P.
B.G.P.
C.H.P.
D.none
Solution
In + In+2 = 
(tann x + tann+2 x)dx, n ≥ 2
=
tann x sec2 x dx = 
∴ I2 + I4 = 1/3, I3 + I5 = 1/4, I4 + I6 = 1/5 etc.
∴
are in A.P.
(tann x + tann+2 x)dx, n ≥ 2=
tann x sec2 x dx = ∴ I2 + I4 = 1/3, I3 + I5 = 1/4, I4 + I6 = 1/5 etc.
∴
are in A.P.
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