Definite IntegrationHard

Question

The area bounded by the curve x = acos3t, y = a sin3 t is

Options

A.
B.
C.
D.3πa2

Solution

x = acos3t,  y = asin3t  ⇒  x2/3 + y2/3 = a2/3
A = sin3 tcos2t(-sin t)dt
= =
= sq. units

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