Definite IntegrationHard
Question
The area of the region bounded by x = 0, y = 0, x = 2, y = 2, y ≤ ex and y ≥ ln x, is
Options
A.6 - 4 ln 2
B.4 ln 2 - 2
C.2 ln 2 - 4
D.6 - 2 ln 2
Solution
A = 
= 2 ln 2 - 1
⇒ Required area = 4 - 2 (ln 2 - 1) = 6 - 4 ln 2
= 2 ln 2 - 1⇒ Required area = 4 - 2 (ln 2 - 1) = 6 - 4 ln 2
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