Definite IntegrationHard
Question
The area bounded in the first quadrant between the ellipse 
= 1 and the line 3x + 4y =12 is:
= 1 and the line 3x + 4y =12 is: Options
A.6 (π - 1)
B.3 (π - 2)
C.3 (π - 1)
D.none
Solution
Area = 
=
=
[(0 + 4π) - (0 + 0)] - 
[48 - 24]
= 3π - 6 = 3(π - 2)
=
=
[(0 + 4π) - (0 + 0)] - [48 - 24]= 3π - 6 = 3(π - 2)
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