Application of DerivativeHard
Question
For the curve x = t2 + 3t - 8, y = 2t2 - 2t - 5, at point (2, - 1)
Options
A.length of subtangent is 7/6.
B.slope of tangent = 6/7
C.length of tangent = 
/6
/6D.none of these
Solution
x = 2 ⇒ t2 + 3t - 10 = 0 ⇒ t = 2, - 5
y = - 1 ⇒ t2 - t - 2 = 0 ⇒ t = 2, - 1
⇒ t = 2 (common value)
Subtangent =
Tangent =
y = - 1 ⇒ t2 - t - 2 = 0 ⇒ t = 2, - 1
⇒ t = 2 (common value)
Subtangent =
Tangent =
Create a free account to view solution
View Solution FreeMore Application of Derivative Questions
If equation of normal at a point (m2, − m3) on the curve x3 − y2 = 0 is y = 3mx − 4m3, then m2 equals-...If tangent to the curve y = f (x) at any point is parallel to y - axis , then at that point dy/dx equals-...The function is monotonically decreasing at the point...Let Tr be the rth term of an A.P. for r = 1, 2, 3, ........ If for some positive integers m, n we have Tm = & Tn = , the...The angle of intersection between the curves y = 4x2 and y = x2 is-...