Application of DerivativeHard
Question
For the curve x = t2 + 3t - 8, y = 2t2 - 2t - 5, at point (2, - 1)
Options
A.length of subtangent is 7/6.
B.slope of tangent = 6/7
C.length of tangent = 
/6
/6D.none of these
Solution
x = 2 ⇒ t2 + 3t - 10 = 0 ⇒ t = 2, - 5
y = - 1 ⇒ t2 - t - 2 = 0 ⇒ t = 2, - 1
⇒ t = 2 (common value)
Subtangent =
Tangent =
y = - 1 ⇒ t2 - t - 2 = 0 ⇒ t = 2, - 1
⇒ t = 2 (common value)
Subtangent =
Tangent =
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