Application of DerivativeHard
Question
The line 
= 1 touches the curve y = be-x/a at the point
= 1 touches the curve y = be-x/a at the pointOptions
A.(- a, 2b)
B.
C.
D.(0, b)
Solution
= 1 - 
= e-x/a ⇒ e-x/a = 1 -
put t = -
et = 1 + t
Draw graph of y = et, y = 1 + t
From graph it is clear that t = 0 is the only solution
⇒ x = 0 ⇒ y = b (0, b)
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