Application of DerivativeHard
Question
The dimensions of the rectangle of maximum area that can be inscribed in the ellipse
(x/4)2 + (y/3)2 = 1 are
(x/4)2 + (y/3)2 = 1 are
Options
A.√8, √2
B.4, 3
C.2, √8, 3√2
D.√2, √6
Solution
x = 4 cosθ, y = 3 sin θ
Let A be area.
A = 4 (4 cos θ) (3 sin θ)
= 24 sin 2θ
A is maximum when 2 θ = π/2
⇒ Dimensions are
Create a free account to view solution
View Solution FreeMore Application of Derivative Questions
The point where the tangent to the curve xy + 4 = 0 is equally inclined with both axes are-...Slope of common tangent to y2 = 4x and x2 + 4y2 = 8 is...The point where the tangent line to the curve y = e2x at (0, 1) meets x-axis is -...If a, b > 0 and ᐃ (x) = , then -...On the curve x3 = 12y. The interval in which abscissa changes at a faster rate then its ordinate...