Binomial TheoremEasy
Question
If the mean and the variance of a binomial variate X are 2 and 1 respectively, then the probability that X takes a value greater than or equal to one is :
Options
A.9/16
B.3/4
C.1/16
D.15/16
Solution
mean = np = 2 ......... (1)
variance npq = 1 ......... (2)
by (2) and (1)
q =
p =
⇒ n = 4
P(x ≥ 1) = 4C1p1q3 + 4C2p2q2 + 4C3p3q + 4C4p4
= 1 - 4C0p0q4
= 1 -
variance npq = 1 ......... (2)
by (2) and (1)
q =
p =
⇒ n = 4
P(x ≥ 1) = 4C1p1q3 + 4C2p2q2 + 4C3p3q + 4C4p4
= 1 - 4C0p0q4
= 1 -
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