Set, Relation and FunctionEasy
Question
If the two roots of the equation, (a − 1)(x4 + x2 + 1) + (a + 1)(x2 + x + 1)2 = 0 are real and distinct, then the set of all values of ′a′ is :
Options
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Solution
Equation be cames
(a - 1)(x2 - x + 1) + (a + 1)(x2 + x + 1) = 0
ax2 + x + a = 0
for roots to be distinct and real a ≠ 0 and 1 - ha2 > 0
⇒ a ∈
(a - 1)(x2 - x + 1) + (a + 1)(x2 + x + 1) = 0
ax2 + x + a = 0
for roots to be distinct and real a ≠ 0 and 1 - ha2 > 0
⇒ a ∈
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