CircleHard
Question
If the incentre of an equilateral triangle is (1, 1) and the equation of its one side is 3x + 4y + 3 = 0, then the
equation of the circumcircle of this triangle is :
equation of the circumcircle of this triangle is :
Options
A.x2 + y2 − 2x − 2y − 14 = 0
B.x2 + y2 − 2x − 2y − 2 = 0
C.x2 + y2 − 2x − 2y + 2 = 0
D.x2 + y2 − 2x − 2y − 7 = 0
Solution
Let radius is r
⇒
⇒ r = 4
So circle is
(x - 1)2 + (y - 1)2 = 16
⇒ x2 + y2 - 2x - 2y - 14 = 0
⇒
⇒ r = 4So circle is
(x - 1)2 + (y - 1)2 = 16
⇒ x2 + y2 - 2x - 2y - 14 = 0
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