Atomic StructureHard
Question
A + 3B + 3C ⇋ AB2C3
Reaction of 6.0 g of A, 6.0 × 1023 atoms of B, and 0.036 mol of C yields 4.8 g of compound AB2C3. If the atomic mass of A and C are 60 and 80 amu, respectively, the atomic mass of B is (Avogadro no. = 6 ×1023):
Reaction of 6.0 g of A, 6.0 × 1023 atoms of B, and 0.036 mol of C yields 4.8 g of compound AB2C3. If the atomic mass of A and C are 60 and 80 amu, respectively, the atomic mass of B is (Avogadro no. = 6 ×1023):
Options
A.50 amu
B.60 amu
C.70 amu
D.40 amu
Solution
nA = 0.1, nB = 1, nC = 0.036
Limiting reagent = C
⇒ nAB2C3 formed =
= 0.012
⇒ MM(AB2C3)
= 400
⇒ 60 + 2x + 80 × 3 = 400
x = 50
Limiting reagent = C
⇒ nAB2C3 formed =
= 0.012⇒ MM(AB2C3)
= 400⇒ 60 + 2x + 80 × 3 = 400
x = 50
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