Basic Maths and Units and DimensionsHard

Question

A short bar magnet is placed in the magnetic meridian of the earth with north pole pointing north. Neutral points are found at a distance of 30 cm from the magnet on the East - West line, drawn through the middle point of the magnet. The magnetic moment of the magnet in Am2 is close to :
(Given μ0/4π 10-7 in SI units and BH = Horizontal component of earth′s magnetic field = 3.6 × 10-5 Tesla)

Options

A.14.6
B.19.4
C.9.7
D.4.9

Solution

= 3.6 × 10-5
M = (0.3)3
M = 9.7 Am2

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