ElectroMagnetic InductionEasy

Question

When current in a coil changes from 5 A to 2 A in 0.1 s, average voltage of 50V is produced. The self -inductance of the coil is :

Options

A.1.67 H
B.6 H
C.3 H
D.0.67 H

Solution

EMF =
50 = L
⇒   L = = 1.67 H

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