Work, Power and EnergyHard
Question
A block of mass m = 0.1 kg is connected to a spring of unknown spring constant k. It is compressed to a
distance x from rest. After approaching half the distance
from equilibrium position, it hits another block
and comes to rest momentarily, while the other block moves with a velocity 3ms-1. the total initial energy of the spring is
distance x from rest. After approaching half the distance
from equilibrium position, it hits another blockand comes to rest momentarily, while the other block moves with a velocity 3ms-1. the total initial energy of the spring is
Options
A.0.3 J
B.0.6 J
C.1.5 J
D.0.8 J
Solution
Apply momentum conservation
0.1u + m(0) = 0.1(0) + m(3)
0.1u2 = 
(3)2
kx2 = 
(0.1)32
Kx2 = 0.9
Kx2 = 0.6J
0.1u + m(0) = 0.1(0) + m(3)
0.1u2 = (3)2kx2 = (0.1)32Kx2 = 0.9Kx2 = 0.6JCreate a free account to view solution
View Solution FreeMore Work, Power and Energy Questions
Two bodies of mass m and 4m are moving with equal kinetic energy. Then the ratio oftheir liner momentum will be:...The relation between conservative force and potential energy U is given by :-...A particle of mass m is initially at rest at the origin. It is subjected to a force and starts moving along the x-axis. ...A body of mass m moving with velocity v collides head on with another body of mass 2m which is initially at rest. The ra...At what temperature, the mean kinetic energy O2 will be the same for H2 molecules at -73oC :-...