BiomoleculesHard
Question
Length of one turn of the helix in a B-form DNA is approximately
Options
A.3.4 nm
B.2 nm
C.0.34 nm
D.20 nm
Solution
B-form of DNA shows right handed coiling which contains 10 base pairs in each turn. One complete turn of DNA occupies 34 
distance so, in nm it will 3.4 nm because
1 nm = 10-9 m
1 = 10-10 m
34 = 34 × 10-10 m
or = 3.4 × 10-9 m
So, = 3.4 nm
distance so, in nm it will 3.4 nm because 1 nm = 10-9 m
1
= 10-10 m34
= 34 × 10-10 mor = 3.4 × 10-9 m
So, = 3.4 nm
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