AIPMT | 2015ElectrostaticsHard
Question
The electric field in a certain region is acting radially outward and is given by E = Ar. A charge contained in a shepere of radius ′a′ centred at the origin of the field, will be given by :
Options
A.A ε0 a2
B.4 πε0 Aa3
C.ε0 Aa3
D.4 πε0 Aa2
Solution
Flux linked with sphere = 
since electric field is radial. It is always perpendicular
to the surface.
so φ - Ar. (4πr2)
φ - A (a)(4πr2) (as r = a)
φ - A4πa3)
Now according to gauss law
φ =
⇒ qin = φ.∈0
so qin = A4πa3∈0
Hence option (2)
since electric field is radial. It is always perpendicular
to the surface.
so φ - Ar. (4πr2)
φ - A (a)(4πr2) (as r = a)
φ - A4πa3)
Now according to gauss law
φ =
⇒ qin = φ.∈0so qin = A4πa3∈0
Hence option (2)
Create a free account to view solution
View Solution FreeMore Electrostatics Questions
Two similar spheres having +q and -q charges are kept at a certain distance. F force acts between the two. If in the mid...You are given an arrangement of three point charges q, 2q and xq separated by equal finite distances so that electric po...A charge is placed at a distance r from the axis of dipole. Force acting on it is F. If distance is made to double then ...An imaginary closed surface P is constructed around a neutral conducting wire connected to a battery and a switch as sho...The electrostatic potential inside a charged spherical ball is given by φ = αρ2 + b where r is the distan...