AIPMT | 2015Laws of MotionEasy
Question
Three blocks A, B and C of masses 4 kg, 2 kg and 1 kg respectively, are in contact on a frictionless surface, as shown. If a force of 14 N is applied on the 4 kg block, then the contact force between A and B is :
Options
A.6 N
B.8 N
C.18 N
D.2 N
Solution
Acceleration of system =
=
= 2 m/s2
The contact force between 4 kg & 2 kg block will
move 2 kg & 1 kg block with the same acceleration
so Fcontact = (2 + 1)a = 3(2) = 6N
Hence option (1)
=
= 2 m/s2The contact force between 4 kg & 2 kg block will
move 2 kg & 1 kg block with the same acceleration
so Fcontact = (2 + 1)a = 3(2) = 6N
Hence option (1)
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