GravitationHard
Question
Two spherical bodies of mass M and 5 M and radii R and 2 R are released in free space with initial separation between their centres equal to 12 R. If they attract each other due to gravitational force only, then the distance covered by the smaller body before collision is :
Options
A.4.5 R
B.7.5 R
C.1.5 R
D.2.5 R
Solution

Initial distance between their centers = 12 R

At time of collision the distance between their centers = 3R
So total distance travelled by both =12R-3R = 9R
Since the bodies move under mutual forces, center
of mass will remain stationary so
m1x1 = m2x2
mx = 5m(9R - x)
x = 45R - 5x
6x = 45R
x =
Hence option (2)
Create a free account to view solution
View Solution FreeMore Gravitation Questions
A particle of mass M is at a distance a from surface of a thin spherical shell of equal mass and having radius a...The ratio of escape velocity for earth and orbital velocity of a satellite which is revolving in a orbit near the earth ...A geostationary satellite orbit s arround the earth in a circular orbit of radius 36000 km. Then, the time period of a s...A man of mass m starts falling towards a planet of mass M and radius R. As he reaches near to the surface, he realizes t...The intensity of gravitational field at a point situated at a distance 8000 km from the centre of Earth is 6.0 newton /k...