AIPMT | 2015Sound WavesEasy
Question
The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second overtone of an organ pipe open at both the ends. The length of organ pipe open at both the ends is :-
Options
A.100 cm
B.120 cm
C.140 cm
D.80 cm
Solution
Fundamental frequency of closed organ
pipe =
2nd overtone frequency of open organ pipe =
Now
= 
⇒ l0 = 6lc = 6(20 cm) = 120 cm
pipe =
2nd overtone frequency of open organ pipe =
Now
= ⇒ l0 = 6lc = 6(20 cm) = 120 cmCreate a free account to view solution
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