AIPMT | 2015Magnetic field due to currentEasy
Question
A wire carrying current I has the shape as shown in adjoining figure. Linear parts of the wire are very long and parallel to X-axis while semicircular portion of radius R is lying in Y-Z plane. Magnetic field at point O is :
Options
A.
B.
C.
D.
Solution
′B′ due to segment ′l′
B1 =
[sin 90o + sin θ] (- k)
B1 =
(-k) = B2
B due to segment ′2′
B2 =
(- î)
So ′B′ at center
⇒
Hence option (2)
B1 =
[sin 90o + sin θ] (- k)B1 =
(-k) = B2B due to segment ′2′
B2 =
(- î)So ′B′ at center
⇒
Hence option (2)
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