ThermodynamicsHard
Question
A gas undergoes an adiabatic process in which pressure becomes 
times and volume become 
of initial volume. If initial absolute temperature was T, the final temperature is
times and volume become of initial volume. If initial absolute temperature was T, the final temperature isOptions
A.
B.
C.T3/2
D.
Solution
For adiabatic processP1V1γ = P2V2γ ⇒ P0V0γ = 
...(i)
Also, T1V1γ-1 = T2V2γ-1 ⇒ TV0γ-1 = T2
...(ii)
Solving (i) & (ii), T2 =
...(i)Also, T1V1γ-1 = T2V2γ-1 ⇒ TV0γ-1 = T2
...(ii)Solving (i) & (ii), T2 =
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