ThermodynamicsHard
Question
One mole of an ideal gas undergoes a process whose molar heat capacity is 4R and in which work done by gas for small change in temperature is given by the relation dW = 2RdT, then the ratio 
is
isOptions
A.7/5
B.5/3
C.3/2
D.2
Solution
For small change dq = du + dw
nCdT = nCV dT + 2nRdT
∴ C = CV + 2R; 4R = CV + 2R
∴ CV = 2R
Also CV =
= 2R ⇒ 2γ - 2 = 1 ⇒ γ = 
nCdT = nCV dT + 2nRdT
∴ C = CV + 2R; 4R = CV + 2R
∴ CV = 2R
Also CV =
= 2R ⇒ 2γ - 2 = 1 ⇒ γ = Create a free account to view solution
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