Trigonometric EquationHard
Question
In ᐃABC, which of the following is/are possible (where notations have usual meaning)
Options
A.sin A : sin B : sin C = 1 : 2 : 3
B.ᐃ = 
C.(a + b + c)(a + b - c) = 3ab
D.b2 - c2 = aR
Solution
(A) a : b : c = 1 : 2 : 3
(B) ᐃ =
bc sin A = 
sin A =
(possible)
(C) (a + b)2 - c2 = 3ab
a2 + b2 - c2 = ab
cos C =
(possible)
(D) 4R2(sin2B - sin2C) = 2R2sin A
sin (B + C) sin (B - C) =
sin A
sin(B - C) =
(possible)
(B) ᐃ =
bc sin A = sin A =
(possible)(C) (a + b)2 - c2 = 3ab
a2 + b2 - c2 = ab
cos C =
(possible)(D) 4R2(sin2B - sin2C) = 2R2sin A
sin (B + C) sin (B - C) =
sin Asin(B - C) =
(possible)Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
If = 0. So find the general value of θ...The value of the integral cos x dx is...Let f : (0, 1) → R be defined by f(x) , where b is a constant such that 0...If 0 , then tanx is...The most general value of q which satisfies both the equations tanπ = √3 and cosec θ = − is -...