JEE Advanced | 2013Photoelectric EffectHard
Question
A pulse of light of duration 100 ns is absorbed completely by a small object initially at rest. Power of the pulse is 30 mW and the speed of light is 3 × 108 ms-1. The final momentum of the object is :-
Options
A.0.3 × 10-17 kg ms-1
B.1.0 × 10-17 kg ms-1
C.3.0 × 10-17 kg ms-1
D.9.0 × 10-17 kg ms-1
Solution
Energy incident = P (time)
= 30 mW (100 ns)
= 3 × 10-9
So momentum
10-17 kg m/sec.Create a free account to view solution
View Solution FreeMore Photoelectric Effect Questions
Photons of energy 5.5 eV fall on the surface of the metal emitting photoelectrons of maximum kinetic energy 4.0 eV. The ...The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy 6 eV fall on it is 4 eV. The ...Consider a metal used to produced some charateristic X-rays. Energy of X-rays are given by E and wavelength as represent...If an orbital electron of the hydrogen atom jumps from the ground state to a higher energy state, its orbital speed redu...The slope of graph drawn between stopping potential and frequency of incident light for a given surface will be :-...