JEE Advanced | 2013Photoelectric EffectHard
Question
A pulse of light of duration 100 ns is absorbed completely by a small object initially at rest. Power of the pulse is 30 mW and the speed of light is 3 × 108 ms-1. The final momentum of the object is :-
Options
A.0.3 × 10-17 kg ms-1
B.1.0 × 10-17 kg ms-1
C.3.0 × 10-17 kg ms-1
D.9.0 × 10-17 kg ms-1
Solution
Energy incident = P (time)
= 30 mW (100 ns)
= 3 × 10-9
So momentum
10-17 kg m/sec.Create a free account to view solution
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